document.write( "Question 1039394: Solve equation or inequality\r
\n" ); document.write( "\n" ); document.write( "10-sqrt(x-2<=11)
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Algebra.Com's Answer #654182 by Fombitz(32388)\"\" \"About 
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Graphing the functions,
\n" ); document.write( "\"y=10-sqrt%28x-2%29\"
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\n" ); document.write( "\"y=11\"
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\n" ); document.write( "It looks like \"10-sqrt%28x-2%29%3C=11\" for all x where it's defined,
\n" ); document.write( "\"x%3E=2\".
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\n" ); document.write( "Algebraically,
\n" ); document.write( "\"10-sqrt%28x-2%29%3C=11\"
\n" ); document.write( "\"sqrt%28x-2%29%3E=-1\"
\n" ); document.write( "By definition, the square is always non-negative so it holds for all x, where degined.
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