document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1039330>Question 1039330</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello ! I need help with this problem. At first I thought I had solved it, but then whoops, I calculated 3 means instead of 5, and upon looking closer, I discovered that my whole process was utterly wrong... I looked at my book for help, but it didn't really make me understand anything. So here's the question: Insert 5 arithmetic means between (x+3y) and (9y-5x). I'll appreciate any help, thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #654160 by </B><A HREF=/tutors/aboutme.mpl?userid=FrankM><B>FrankM(1040)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=FrankM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=FrankM><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=654160\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To add 5 arithmetic means to 1, , , , , , 7 is simple, for the fact that there are 6 'differences', and the total difference is 6. So we get, 1,2,3,4,5,6,7.\r<BR>\n" );
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document.write( "To get from x to -5x is the same, it's 6 differences of x, -x to be clear. The same for 3y to 9y, it's just a difference of y. \r<BR>\n" );
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document.write( "(x+3y) (0x+4y)(-1x+5y)(-2x+6y)(-3x+7y)(-4x+8y) (-5x+9y)<BR>\n" );
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