document.write( "Question 1039350: Hello! In this problem, I had some trouble: \"Find the value of t(subscript 2) + t(sub3) + t(sub4) + ... + t(sub 98) if t (sub 1) + t (sub 2) t (sub 3)... is an arithmetic progression with the common difference = 1, and S (sub 98) = 137.\r
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Algebra.Com's Answer #654149 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
You know that the sum of an arithmetic progression in terms of common difference and first term is,
\n" ); document.write( "\"S%5Bn%5D=%28n%2F2%29%282t%5B1%5D%2B%28n-1%29%2Ad%29\"
\n" ); document.write( "So,
\n" ); document.write( "\"S%5B98%5D=%2898%2F2%29%282t%5B1%5D%2B%2898-1%29%2A1%29\"
\n" ); document.write( "\"137=49%282t%5B1%5D%2B97%29\"
\n" ); document.write( "\"2t%5B1%5D%2B97=137%2F49\"
\n" ); document.write( "\"2t%5B1%5D=137%2F49-97\"
\n" ); document.write( "\"t%5B1%5D=137%2F98-97%2F2\"
\n" ); document.write( "Now that you have the first term you can subtract it from the sum to get the value that you're looking for.
\n" ); document.write( "\"t%5B1%5D%2BX=S%5B98%5D\"
\n" ); document.write( "\"137%2F98-97%2F2%2BX=137\"
\n" ); document.write( "\"X=137-137%2F98%2B97%2F2\"
\n" ); document.write( "or with a common denominator,
\n" ); document.write( "\"X=9021%2F49\" \r
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