document.write( "Question 1039419: how can you write 5-3x=2xsqaured in standard form?
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Algebra.Com's Answer #654144 by Edwin McCravy(20054)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"5-3x\"\"%22%22=%22%22\"\"2x%5E2\"\r\n" );
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document.write( "Standard form is \"Ax%5E2%2BBx%2BC\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "where A is a positive number.\r\n" );
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document.write( "\"5-3x\"\"%22%22=%22%22\"\"2x%5E2\"\r\n" );
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document.write( "Add -2x2 to both sides\r\n" );
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document.write( "\"5-3x-red%282x%5E2%29\"\"%22%22=%22%22\"\"2x%5E2-red%282x%5E2%29\"\r\n" );
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document.write( "Rearrange terms in descending order on the left.\r\n" );
document.write( "Right side becomes 0:\r\n" );
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document.write( "\"-2x%5E2-3x%2B5\"\"%22%22=%22%22\"\"0\"\r\n" );
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document.write( "Since first term is negative, multiply every term by -1:\r\n" );
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document.write( "\"2x%5E2%2B3x-5\"\"%22%22=%22%22\"\"0\"  <--- that's in standard form.  That's\r\n" );
document.write( "                        all you were asked to do.  But\r\n" );
document.write( "                        I'll go ahead and solve it.  \r\n" );
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document.write( "Factor the left side:\r\n" );
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document.write( "\"%282x%2B5%29%28x-1%29\"\"%22%22=%22%22\"\"0\"\r\n" );
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document.write( "Use zero-factor property:\r\n" );
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document.write( "\"2x%2B5\"\"%22%22=%22%22\"\"0\";   \"x-1\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "  \"2x\"\"%22%22=%22%22\"\"-5\";    \"x\"\"%22%22=%22%22\"\"1\"\r\n" );
document.write( "   \"x\"\"%22%22=%22%22\"\"-5%2F2\"\r\n" );
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document.write( "Edwin
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