document.write( "Question 1039403: A and B can do a work in 12 days,B and C in 16 days. A started work and afte 7 days he stopd work and B started the work,after 5days B stopd work and remaining work was completed by C in 13days. In how many days A ,B,C alone can finish the work. \n" ); document.write( "
Algebra.Com's Answer #654133 by josgarithmetic(39630)\"\" \"About 
You can put this solution on YOUR website!
a, b, c, the times in days for A, B, and C to do \"one whole work\". Use the work rates as \"1%2FT\" in unit of \"JOB%2FDAYS\".\r
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\n" ); document.write( "\n" ); document.write( "\"system%281%2Fa%2B1%2Fb=1%2F12%2C1%2Fb%2B1%2Fc=1%2F16%29\"\r
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\n" ); document.write( "\n" ); document.write( "A sequence of workers has done one whole job.
\n" ); document.write( "\"%281%2Fa%297%2B%281%2Fb%295%2B%281%2Fc%2913=1\"\r
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\n" ); document.write( "\n" ); document.write( "Goal is to solve for a, b, and c.\r
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\n" ); document.write( "\n" ); document.write( "Use the first two equations to solve each in terms of b.
\n" ); document.write( "-
\n" ); document.write( "\"1%2Fa=1%2F12-1%2Fb\"
\n" ); document.write( "\"1%2Fa=%28b-12%29%2F12b\"
\n" ); document.write( "\"highlight_green%28a=12b%2F%28b-12%29%29\"
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\n" ); document.write( "\"1%2Fc=1%2F16-1%2Fb\"
\n" ); document.write( "\"1%2Fc=%28b-16%29%2F16b\"
\n" ); document.write( "\"highlight_green%28c=16b%2F%28b-16%29%29\"
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\n" ); document.write( "Substitute these into the Finished In Thirteen Days equation.
\n" ); document.write( "\"%28%28b-12%29%2F%2812b%29%297%2B%28%28b-16%29%2F%2816b%29%2913=1\"\r
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\n" ); document.write( "\n" ); document.write( "Simplify.
\n" ); document.write( "\"7%28b-12%29%2F%2812b%29%2B13%28b-16%29%2F%2816b%29=1\", and simplest denominator IS 2*2*2*2*3*b;\r
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\n" ); document.write( "\n" ); document.write( "\"%283%2A2%5E4%2Ab%29%287%28b-12%29%2F%2812b%29%2B13%28b-16%29%2F%2816b%29%29=3%2A2%5E4%2Ab\"\r
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\n" ); document.write( "\n" ); document.write( "\"7%2A3%2A2%5E4%2Ab%28b-12%29%2F%2812b%29%2B13%2A3%2A2%5E4%2Ab%28b-16%29%2F%2816b%29=3%2A16b\"\r
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\n" ); document.write( "\n" ); document.write( "\"7%2A4%28b-12%29%2B13%2A3%28b-16%29=54b\"\r
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\n" ); document.write( "\n" ); document.write( "\"28b-336%2B39b-624=48b\"\r
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\n" ); document.write( "\n" ); document.write( "\"28b%2B39b-48b=336%2B624\"\r
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\n" ); document.write( "\n" ); document.write( "\"19b=960\"\r
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\n" ); document.write( "\n" ); document.write( "\"b=960%2F19\"\r
\n" ); document.write( "\n" ); document.write( "\"b=50.53\"------------Seems strange, maybe correct, but needs to be rechecked ... Maybe a mistake was made. If you can understand the process up to here, your work MIGHT be better and without any mistake I made. You could then continue to go back to the first two equations to solve for a and c.
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