document.write( "Question 12989: Hello Again:\r
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document.write( "Thanks for your help. I appreciate it. Here is another equation that I need help on. I am trying hard to get to the root of the answer. Please help me.\r
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document.write( "Solve the systems of linear equation:\r
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document.write( "5x - 2y = 1
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document.write( "2x = y + -4\r
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document.write( "Please show me how to do this. I keep getting stuck. I tried the substitution method. Thank you again. \n" );
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Algebra.Com's Answer #6541 by pwac(253)![]() ![]() ![]() You can put this solution on YOUR website! 5x-2y=1----1 \n" ); document.write( "2x=y-4-----2 (note:y+ -4 can be written y-4) \n" ); document.write( "Re-arrange equ.2 to get \n" ); document.write( "y=2x+4-----3 Substitute y=2x+4 into equ.1 \n" ); document.write( "5x-2(2x+4)=1 Expand bracket by multipying by -2 \n" ); document.write( "5x-4x-8=1 \n" ); document.write( "x-8=1 Subtract-8 from both sides to get x \n" ); document.write( "x=1-(-8) \n" ); document.write( "x=9 Put x=9 into equ.3 to find y \n" ); document.write( "y=2X9 +4 =18+4 \n" ); document.write( "y=22 \n" ); document.write( "To check use values of x and y in either equation 1 or 2.Let's use 1 \n" ); document.write( "5X9 - 2X22=1 \n" ); document.write( "45-44 does indeed =1 Hope this helps \n" ); document.write( "Pete \n" ); document.write( " \n" ); document.write( " |