document.write( "Question 1039340: divide $1500between a,b and c such that b share is five-sixth of a share and c share is four-fifth of b share \n" ); document.write( "
Algebra.Com's Answer #654078 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Write an equation for each phrase, get all three in terms of b \n" ); document.write( ": \n" ); document.write( " divide $1500 between a,b and c \n" ); document.write( "a + b + c = 1500 \n" ); document.write( ": \n" ); document.write( " such that b share is five-sixth of a share \n" ); document.write( "b = \n" ); document.write( "multiply both sides by 6 \n" ); document.write( "6b = 5a \n" ); document.write( "divide both sides by 5 \n" ); document.write( "a = \n" ); document.write( ": \n" ); document.write( " and c share is four-fifth of b share \n" ); document.write( "c = \n" ); document.write( ": \n" ); document.write( "Now we substitute for a and c and have: \n" ); document.write( " \n" ); document.write( "multiply by 5, get rid of the denominators \n" ); document.write( "6a + 5b + 4b = 5(1500) \n" ); document.write( "15b = 7500 \n" ); document.write( "b = 7500/15 \n" ); document.write( "b = $500 is b's share \n" ); document.write( "then \n" ); document.write( "a = \n" ); document.write( "a = $600 is a's \n" ); document.write( "and \n" ); document.write( "c = \n" ); document.write( "c = $400 is c's \n" ); document.write( ": \n" ); document.write( "They add up to $1500 \n" ); document.write( " \n" ); document.write( " |