document.write( "Question 1039340: divide $1500between a,b and c such that b share is five-sixth of a share and c share is four-fifth of b share \n" ); document.write( "
Algebra.Com's Answer #654078 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Write an equation for each phrase, get all three in terms of b
\n" ); document.write( ":
\n" ); document.write( " divide $1500 between a,b and c
\n" ); document.write( "a + b + c = 1500
\n" ); document.write( ":
\n" ); document.write( " such that b share is five-sixth of a share
\n" ); document.write( "b = \"5%2F6\"a
\n" ); document.write( "multiply both sides by 6
\n" ); document.write( "6b = 5a
\n" ); document.write( "divide both sides by 5
\n" ); document.write( "a = \"6%2F5\"b
\n" ); document.write( ":
\n" ); document.write( " and c share is four-fifth of b share
\n" ); document.write( "c = \"4%2F5\"b
\n" ); document.write( ":
\n" ); document.write( "Now we substitute for a and c and have:
\n" ); document.write( "\"6%2F5\"b + b + \"4%2F5\"b = 1500
\n" ); document.write( "multiply by 5, get rid of the denominators
\n" ); document.write( "6a + 5b + 4b = 5(1500)
\n" ); document.write( "15b = 7500
\n" ); document.write( "b = 7500/15
\n" ); document.write( "b = $500 is b's share
\n" ); document.write( "then
\n" ); document.write( "a = \"6%2F5\"*500
\n" ); document.write( "a = $600 is a's
\n" ); document.write( "and
\n" ); document.write( "c = \"4%2F5\"*500
\n" ); document.write( "c = $400 is c's
\n" ); document.write( ":
\n" ); document.write( "They add up to $1500
\n" ); document.write( "
\n" ); document.write( "
\n" );