document.write( "Question 1039320: Find the inverse function of f.
\n" ); document.write( "f(x)= x^3 - 2
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Algebra.Com's Answer #654056 by Theo(13342)\"\" \"About 
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set y = f(x)
\n" ); document.write( "equation becomes y = x^3 - 2
\n" ); document.write( "replace y with x and x with y and the equation becomes x = y^3 - 2
\n" ); document.write( "that is the inverse equation.
\n" ); document.write( "you can solve it for x or you can leave it as is, and graph it.
\n" ); document.write( "some software allows you to graph it as is.
\n" ); document.write( "other software requires you to solve it for y.
\n" ); document.write( "you can also graph it manually but that's labor intensive.
\n" ); document.write( "i graphed it both ways (as is) and after solving for y just to show you it's the same graph.
\n" ); document.write( "i also graphed the original equation and y = x.
\n" ); document.write( "if it is the inverse equation, then it will be a reflection o the original equation about the line y = x.
\n" ); document.write( "i also graphed the line y = -x + 8.
\n" ); document.write( "this line is perpendicular to the line y = x and shows two selected points, one on the original equation and one on the inverse equation, that show they are reflections about the line y = x because (x,y) on the original equation is equal to (y,x) on the inverse equation.
\n" ); document.write( "check out the graph to see what i mean.
\n" ); document.write( "the equations in blue are the inverse equations.
\n" ); document.write( "the original equation is red.
\n" ); document.write( "(x+2)^(1/3) is the same as the cube root of (x+2).
\n" ); document.write( "solving for y, start with x = y^3 - 2
\n" ); document.write( "add 2 to both sides of the equation to get x+2 = y^3
\n" ); document.write( "take the cube root of both sides of the equation to get y = cube root of (x+2).
\n" ); document.write( "here's the graph.
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