document.write( "Question 1039273: HELP!!! Determine the values of the variable for which the expression is defined as a real number(answer in interval notation)?\r
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document.write( "1. Sqrt of 5(x)^2 -7x+2 \r
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document.write( "2. (x)^5 +(x)^3 greater or equal to (x)^2 +5x. (Interval notation rounded to two decimals). \n" );
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Algebra.Com's Answer #654016 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! the first is where 5x^2-7x+2>=0 \n" ); document.write( "(5x-2)(x-1)> = 0 \n" ); document.write( "the roots are x=(2/5) and x=1 \n" ); document.write( "Between these, the value is <0 \n" ); document.write( "so the intervals are(-oo,2/5] and [1,oo) \n" ); document.write( " \n" ); document.write( "================ \n" ); document.write( "x^5+x^3>=x^2+5x \n" ); document.write( "x^5+x^3-x^2-5x>=0. \n" ); document.write( "This is <0 when x <-1.23 \n" ); document.write( "It is >=0 when x is between -1.23 and 0 \n" ); document.write( "It is <0 when x is between (0,1.44) \n" ); document.write( "It is >0 when x>=1.44 \n" ); document.write( "[-1.23,0]U[1.44,oo] \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |