document.write( "Question 1827: Question: how i can solve this equation.
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document.write( "x + y^(.5) = 7
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document.write( "y + x^(.5) = 11
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document.write( "i know the answer of these equations but dont know how to solve ?
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document.write( "meance in first equation just y plus x to the power .5 and in second equation swap x and y.
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document.write( "answer is x = 4 ...... and y = 9
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document.write( "but i want to know the method for solving this equation :-) \n" );
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Algebra.Com's Answer #654 by khwang(438)![]() ![]() ![]() You can put this solution on YOUR website! You can use substitution tosolve this system of equations.\r \n" ); document.write( "\n" ); document.write( " Solve x + y^(1/2) = 7,,,(1) \n" ); document.write( " y + x^(1/2) = 11...(2) \n" ); document.write( " Sol: y^(1/2) = 7 - x, y = (7 - x)^2 \n" ); document.write( " (7 - x)^2 + x^(1/2) = 11. \n" ); document.write( " Simplify: x^(1/2) + 38 - 14x + x^2 =0, \n" ); document.write( " Let X = x^(1/2), \n" ); document.write( " X^4 - 14X^2 + X + 38 = 0..(**) \n" ); document.write( " Factor: (X-2)(X^3 + 2X^2 -10 X -19) = 0. \n" ); document.write( " So,X = 2 is a root and hence x = X^2 = 4. \n" ); document.write( " Hence, y = (7 - x)^2 = (7 - 4)^2 = 9 \n" ); document.write( " Thus,we obtain a set of solution , x=4, y = 9.\r \n" ); document.write( "\n" ); document.write( " Check: x + y^(1/2) = 4+ 9^(1/2) = 4+3 =7,,,(OK) \n" ); document.write( " y + x^(1/2) = 9 + 4^(1/2) = 9 + 2 =11...(OK)\r \n" ); document.write( "\n" ); document.write( " Note: there is another positive real solution x of(**) between 3 & 4, \n" ); document.write( " but it isin very complicated from. \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( " Kenny \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |