document.write( "Question 1039246: A plane travels at a speed of 160 mph in still air. Flying with a tailwind the plane is clocked over a distance of 800 miles. Flying against a headwind, it takes 3 hours longer to complete the return trip. What was the wind velocity? \n" ); document.write( "
Algebra.Com's Answer #653989 by ankor@dixie-net.com(22740)\"\" \"About 
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A plane travels at a speed of 160 mph in still air.
\n" ); document.write( " Flying with a tailwind the plane is clocked over a distance of 800 miles.
\n" ); document.write( " Flying against a headwind, it takes 3 hours longer to complete the return trip.
\n" ); document.write( " What was the wind velocity?
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\n" ); document.write( "let w = the velocity of the wind
\n" ); document.write( "then
\n" ); document.write( "(160+w) = the effective speed with the wind
\n" ); document.write( "and
\n" ); document.write( "(160-w) = the effective speed against
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( "Against time - with time = 3 hr
\n" ); document.write( "\"800%2F%28%28160-w%29%29\" - \"800%2F%28%28160%2Bw%29%29\" = 3
\n" ); document.write( "Multiply equation by (160-w)(160+w), cancel the denominators
\n" ); document.write( "800(160+w) - 800(160-w) = 3(160-w)(160+w)
\n" ); document.write( "128000 + 800w - 128000 + 800w = 3(25600-w^2)
\n" ); document.write( "1600w = 76800 - 3w^2
\n" ); document.write( "Form a quadratic equation on the left
\n" ); document.write( "3w^2 + 1600w - 76800 = 0
\n" ); document.write( "Use the quadratic formula to find w: a=3; b=1600; c=-76800
\n" ); document.write( "I got a positive solution of
\n" ); document.write( "w = 44.32 mph is the speed of the wind
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\n" ); document.write( "Check this by finding the actual time each way
\n" ); document.write( "800/(160-44.32) = 6.915 hrs
\n" ); document.write( "800/(160+44.32) = 3.915 hrs
\n" ); document.write( "----------------------------
\n" ); document.write( "travel time diff: 3 hrs
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