document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1039198>Question 1039198</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the user is charge p 300 monthly for a particular mobile plan, which includes 100 free text messages. <BR>\n" );
document.write( "messages in excess of 100 are charged p 1 each.<BR>\n" );
document.write( "represent the amount t a consumer pays each month as a function of the number of messages m sent in a month<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #653971 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=653971\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> this would be a partial function or what might be called a split function.\r<BR>\n" );
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document.write( "t = 300 for x <= 100\r<BR>\n" );
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document.write( "t = 300 + 1 * (x-100) for x > 100.\r<BR>\n" );
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document.write( "as long as the number of messages is less than or equal to 100, the first formula of t = 300 is used.\r<BR>\n" );
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document.write( "if the number of messages exceeds 100, then the second formula of t = 300 + 1 * (x - 100) is used.\r<BR>\n" );
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document.write( "assume the customer used 150 messages.<BR>\n" );
document.write( "since the number of messages is greater than 100, the second formula kicks in.<BR>\n" );
document.write( "the monthly charge is 300 + 1 * (150 - 100) = 300 + 1 * 50 = 300 + 50 = 350.\r<BR>\n" );
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document.write( "assume the customer used 90 messages.<BR>\n" );
document.write( "since the number of messages is less than or equal to 100, the first formula kicks in.<BR>\n" );
document.write( "the monthly charge is 300.\r<BR>\n" );
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