document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1039200>Question 1039200</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the general equation of a line passing through (0,k) and (k,k^2) given that k is not equal to 0\r<BR>\n" );
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document.write( "So you find the gradient, which is k-1, then what do you do? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #653941 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=653941\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Slope is k^2-k/k=k-1.<BR>\n" );
document.write( "Use point slope formula on both points<BR>\n" );
document.write( "y-k^2=(k-1)(x-k)<BR>\n" );
document.write( "y-k^2=kx-k^2-x+k<BR>\n" );
document.write( "y=kx+k-x, or x(k-1)+k<BR>\n" );
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document.write( "use other point<BR>\n" );
document.write( "y-k-(k-1)x<BR>\n" );
document.write( "y=(k-1)x +k<BR>\n" );
document.write( "This is the general equation,<BR>\n" );
document.write( "if k=4, y=3x+4, and it would pass through (0,4) and (4,16) </SPAN>\n" );
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