document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1039197>Question 1039197</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Andy canoed downriver for 2 hours and returned in 3 hours. Andy's sped in still water is 2 mi/hr faster than the sped of the current. If W represents speed in still water and C represents speed of the current, what is Andy's still-water paddling speed and the speed of the current? I have tried to answer it but I keep getting 3.5 mi/hr as paddling speed and 1.5 mi/hr as speed of the current. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #653940 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=653940\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=speed in still water mi/hr<BR>\n" );
document.write( "C=speed of current<BR>\n" );
document.write( "2(W+C)=miles paddled in 2 hours<BR>\n" );
document.write( "that equals 3(W-C) coming back.<BR>\n" );
document.write( "Distributing,<BR>\n" );
document.write( "2W+2C=3W-3C<BR>\n" );
document.write( "W=5C<BR>\n" );
document.write( "but C=W-2<BR>\n" );
document.write( "distributing again<BR>\n" );
document.write( "W=5W-10<BR>\n" );
document.write( "-4W=-10<BR>\n" );
document.write( "W=2.5 mph<BR>\n" );
document.write( "C=0.5 mph;W=5C and W=C-2<BR>\n" );
document.write( "3.0 mph together, 2 mph against.<BR>\n" );
document.write( "In 2 hours, goes 6 miles downstream<BR>\n" );
document.write( "In 3 hours, goes 6 miles upstream<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );