document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1039180>Question 1039180</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A passenger train can travel 245 miles in the same amount of time it takes a freight train to travel 200 miles. If the rate of the passenger train is <BR>\n" );
document.write( "15 MPH faster than the rate of the freight train, find the rate of each. <BR>\n" );
document.write( "Set up a table and solve using an algebraic equation. Write write a complete sentence answer.\r<BR>\n" );
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document.write( "How do I even begin to start ?<BR>\n" );
document.write( "Thank you  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #653922 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=653922\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let r be the rate of the freight train. The passenger train goes r+15. So:<BR>\n" );
document.write( "245/r+15=200/r<BR>\n" );
document.write( "245r=200r+3000<BR>\n" );
document.write( "45r=3000<BR>\n" );
document.write( "r=66-2/3<BR>\n" );
document.write( "r+15=81-2/3!!!!!!!!!!!!!!!!!!\r<BR>\n" );
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document.write( "245/r is 245 divided by r, which represents the time taken by the freight train......<BR>\n" );
document.write( "Cross-multiplying 245/(r+15)=200/r, we get:<BR>\n" );
document.write( "245r=200(r+15)<BR>\n" );
document.write( "245r=200r+3000<BR>\n" );
document.write( "etc.......... </SPAN>\n" );
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