document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1039182>Question 1039182</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A jogger who can run a 10-minute mile starts a half-mile ahead of a jogger who can run an 8-minute mile. How long will it take the faster jogger to catch the slower jogger? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #653920 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=653920\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first jogger runs 1/10th a mile per minute; the second one does 1/8th. With a 5/10ths mile head start, or 5 minutes. So:<BR>\n" );
document.write( "n/10+5=n/8<BR>\n" );
document.write( "4n+200=5n<BR>\n" );
document.write( "n=200 minutes before the faster jogger catches up!!!!!! </SPAN>\n" );
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