document.write( "Question 1021817: given four consecutive odd numbers. when the square of the second number is subtracted from the product of the first and last numbers, the answer is 14. find them \n" ); document.write( "
Algebra.Com's Answer #653903 by jorel555(1290) ![]() You can put this solution on YOUR website! Let n be your first number. Then the next numbers would be: n+2,n+4, and n+6. So \n" ); document.write( "(n)(n+6)-(n+2)²=14 \n" ); document.write( "n²+6n-n²-4n-4=14 \n" ); document.write( "2n=18 \n" ); document.write( "n=9 \n" ); document.write( "Your numbers are 9,11,13,and 15!!!!!!!!!!!!!!! \n" ); document.write( " |