document.write( "Question 1039131: All coffee mugs in an office were placed into 4 boxes. The first box when divided by 5, the second box when divided by 4, the third box when divided by 3 and the fourth box when divided by 6 resulted in the same whole number. What is the least of number of mugs that could have been in the office? \n" ); document.write( "

Algebra.Com's Answer #653868 by Theo(13342) $\"\"$ $\"About$

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let that same number be equal to x.
\n" ); document.write( "you get:
\n" ); document.write( "the first box contains 5x.
\n" ); document.write( "the second box contains 4x.
\n" ); document.write( "the third box contains 3x.
\n" ); document.write( "the fourth box contains 6x.
\n" ); document.write( "the total number of mugs in the 4 boxes is equal to 18x.
\n" ); document.write( "x can't be less than 1, so the smallest number of coffee mugs in the office has to be 18.
\n" ); document.write( "5 in the first box plus 4 in the second box plus 3 in the third box plus 6 in the fourth box = 18 total.\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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