document.write( "Question 1039115: A car's rate is 50 kph. A truck's rate is 40 kph. If the car starts later by 5 km in comparison's to the truck's, how many minutes before the car reaches the truck?\r
\n" ); document.write( "\n" ); document.write( "Is it 30 minutes? But how did you arrive with this answer?
\n" ); document.write( "

Algebra.Com's Answer #653853 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Start a stopwatch when the car leaves.
\n" ); document.write( "Let \"+t+\" = the time on the stopwatch in
\n" ); document.write( "hrs when the car catches up with the truck
\n" ); document.write( "Let \"+d+\" = the distance in km the car travels
\n" ); document.write( "until it catches up with the truck
\n" ); document.write( "---------------------------------------
\n" ); document.write( "Equation for the car:
\n" ); document.write( "(1) \"+d+=+50t+\"
\n" ); document.write( "Equation for the truck:
\n" ); document.write( "(2) \"+d+-+5+=+40t+\"
\n" ); document.write( "--------------------
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+50t+-+5+=+40t+\"
\n" ); document.write( "(2) \"+10t+=+5+\"
\n" ); document.write( "(2) \"+t+=+1%2F2+\"
\n" ); document.write( "------------------
\n" ); document.write( "The car catches up with the truck 1/2 after
\n" ); document.write( "the CAR leaves.This is an important point.
\n" ); document.write( "---------------
\n" ); document.write( "If you wanted to know the time in hrs to catch the truck
\n" ); document.write( "after the truck leaves, you must add in the truck's time
\n" ); document.write( "to travel 5 km
\n" ); document.write( "\"+5+=+40t%5B1%5D+\"
\n" ); document.write( "\"+t%5B1%5D+=+1%2F8+\"
\n" ); document.write( "\"+t+%2B+t%5B1%5D+=+4%2F8+%2B+1%2F8+=+5%2F8+\"
\n" ); document.write( "The car catches the truck 5/8 hr after the TRUCK leaves.
\n" ); document.write( "This isn't what was wanted, so you don't care about it.
\n" ); document.write( "
\n" ); document.write( "
\n" );