document.write( "Question 1039096: A random sample of 1100 car owners in a particular city found 220 car owners who recieved a speeding ticket this year. Find a 95% confidence interval for the true percent of car owners in this city who recieved a speeding ticket this year. Express your results to the nearest hundredth of a percent.
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document.write( "______ to ____% \n" );
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Algebra.Com's Answer #653843 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A random sample of 1100 car owners in a particular city found 220 car owners who recieved a speeding ticket this year. Find a 95% confidence interval for the true percent of car owners in this city who recieved a speeding ticket this year. Express your results to the nearest hundredth of a percent. \n" ); document.write( "------ \n" ); document.write( "p-hat = 220/1100 = 0.2 \n" ); document.write( "ME = 1.96*sqrt[0.2*0.8/1100] = 0.024 \n" ); document.write( "Answer: \r \n" ); document.write( "\n" ); document.write( "0.2 - 0.024% < p < 0.2 + 0.024% \n" ); document.write( "------ \n" ); document.write( "0.2024% < p < 0.2024% \n" ); document.write( "============================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------------- \n" ); document.write( " |