document.write( "Question 1039097: A random sample of 800 registered voters in Flagstaff found 456 registered voters who support immigration reform. Find a 95% confidence interval for the true percent of registered voters in Flagstaff who support immigration reform. Express your results to the nearest hundredth of a percent. .\r
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Algebra.Com's Answer #653830 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Given information
\n" ); document.write( "x = 456 (number of successes)
\n" ); document.write( "n = 800 (sample size)
\n" ); document.write( "Confidence Level = 95%\r
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\n" ); document.write( "\n" ); document.write( "What we want to find: \r
\n" ); document.write( "\n" ); document.write( "We want to find the lower (L) and upper (U) boundaries of the confidence interval\r
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\n" ); document.write( "\n" ); document.write( "The critical value of the 95% confidence interval is z = 1.96 (approximately). You can determine this by using a table like this one. Look at the confidence level 95% (bottom of page) then look directly above it to find the value of 1.960 which is the same as 1.96\r
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\n" ); document.write( "\n" ); document.write( "Sample proportion
\n" ); document.write( "p = x/n = 456/800 = 0.57\r
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\n" ); document.write( "\n" ); document.write( "Standard Error (SE)
\n" ); document.write( "\"SE+=+sqrt%28%28p%2A%281-p%29%29%2Fn%29\"
\n" ); document.write( "\"SE+=+sqrt%28%280.57%2A%281-0.57%29%29%2F800%29\"
\n" ); document.write( "\"SE+=+sqrt%28%280.57%2A%280.43%29%29%2F800%29\"
\n" ); document.write( "\"SE+=+sqrt%280.2451%2F800%29\"
\n" ); document.write( "\"SE+=+sqrt%280.000306375%29\"
\n" ); document.write( "\"SE+=+0.01750357106421\" \r
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\n" ); document.write( "\n" ); document.write( "Margin of Error (ME)
\n" ); document.write( "\"ME+=+z%2ASE\"
\n" ); document.write( "\"ME+=+1.96%2A0.01750357106421\"
\n" ); document.write( "\"ME+=+0.03430699928586\"\r
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\n" ); document.write( "\n" ); document.write( "The lower boundary of the confidence interval is
\n" ); document.write( "\"L+=+p+-+ME\"
\n" ); document.write( "\"L+=+0.57+-+0.03430699928586\"
\n" ); document.write( "\"L+=+0.53569300071414\"
\n" ); document.write( "That turns into 53.569300071414% which rounds to 53.57%\r
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\n" ); document.write( "\n" ); document.write( "So L = 53.57% approximately \r
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\n" ); document.write( "\n" ); document.write( "The upper boundary of the confidence interval is
\n" ); document.write( "\"U+=+p+%2B+ME\"
\n" ); document.write( "\"U+=+0.57+%2B+0.03430699928586\"
\n" ); document.write( "\"U+=+0.60430699928587\"
\n" ); document.write( "That turns into 60.430699928587% which rounds to 60.43%\r
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\n" ); document.write( "\n" ); document.write( "So U = 60.43% approximately\r
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\n" ); document.write( "\n" ); document.write( "To recap, the lower and upper bound (L and U respectively) of the confidence interval is\r
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\n" ); document.write( "\n" ); document.write( "L = 53.57%
\n" ); document.write( "U = 60.43% \r
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\n" ); document.write( "\n" ); document.write( "where the boundaries are in percentage form\r
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\n" ); document.write( "\n" ); document.write( "Final Answer:
\n" ); document.write( "   53.57    to    60.43   %
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