document.write( "Question 1039018: Susan invests
\n" ); document.write( "2
\n" ); document.write( "2 times as much money at
\n" ); document.write( "11\r
\n" ); document.write( "\n" ); document.write( "11% as she does at \r
\n" ); document.write( "\n" ); document.write( "7%. If her total interest after \r
\n" ); document.write( "\n" ); document.write( "1 year is \r
\n" ); document.write( "\n" ); document.write( "$1160, how much does she have invested at each rate?
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Algebra.Com's Answer #653810 by jorel555(1290)\"\" \"About 
You can put this solution on YOUR website!
Let n be the amount invested at 7%. Then:
\n" ); document.write( ".11(2n)+.07(n)=1160
\n" ); document.write( ".22n+.07n=1160
\n" ); document.write( ".29n=1160
\n" ); document.write( "n=1160/.29=$4000 invested at 7%
\n" ); document.write( "2n=$8000 invested at 11%!!!!!!!!!!!!!!!!!
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