document.write( "Question 1039027: solve for the solution set using the 3 different methods
\n" ); document.write( "equation1. x = 1
\n" ); document.write( "equation2. x+y+2 = 0
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Algebra.Com's Answer #653751 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
GRAPHING
\n" ); document.write( "\"graph%28300%2C300%2C-4%2C4%2C-4%2C4%2Cx=1%2C-x-2%29\"-----Cannot put this properly on the page in this site. The graph here appears wrong.\r
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\n" ); document.write( "\n" ); document.write( "SUBSTITUTION
\n" ); document.write( "\"1%2By%2B2=0\"
\n" ); document.write( "\"y=-3\"\r
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\n" ); document.write( "\n" ); document.write( "ELIMINATION
\n" ); document.write( "Are these equations really a good fit for using this method? Too simple.
\n" ); document.write( "\"x%2By%2B2-x=0-1\"
\n" ); document.write( "\"y%2B2=-1\"
\n" ); document.write( "\"y=-1-2\"
\n" ); document.write( "\"y=-3\"\r
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\n" ); document.write( "\n" ); document.write( "The x value was already given.
\n" ); document.write( "The solution to the system is x=1, y=-3.
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