document.write( "Question 90024: Could you please help me with this problem?
\n" ); document.write( "1/(x^2-2x-3)+2/(x^2+2x+1) Thank you!!!
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Algebra.Com's Answer #65375 by uma(370)\"\" \"About 
You can put this solution on YOUR website!
1/(x^2-2x-3)+2/(x^2+2x+1)\r
\n" ); document.write( "\n" ); document.write( "The first denominator = x^2 - 2x - 3\r
\n" ); document.write( "\n" ); document.write( " = x^2 - 3x + x - 3
\n" ); document.write( " = x(x-3) +1(x-3)
\n" ); document.write( " = (x-3)(x+1)
\n" ); document.write( "The second denominator = x^2 + 2x + 1
\n" ); document.write( " = x^2 + x + x + 1
\n" ); document.write( " = x(x+1) + 1(x+1)
\n" ); document.write( " = (x+1)(x+1)\r
\n" ); document.write( "\n" ); document.write( "Now the given question is 1/(x-3)(x+1) + 2/(x+1)(x+1)\r
\n" ); document.write( "\n" ); document.write( " = [(x+1) + (x-3)]/(x-3)(x+1)(x+1)\r
\n" ); document.write( "\n" ); document.write( " = (2x - 2)/ (x-3)(x+1)(x+1)\r
\n" ); document.write( "\n" ); document.write( " = 2(x-1)/(x-3)(x+1)(x+1)\r
\n" ); document.write( "\n" ); document.write( "Good luck!!!
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