document.write( "Question 89963: solve by using the quadratic formula
\n" ); document.write( "4x^2-3x+3=0 \n" ); document.write( "

Algebra.Com's Answer #65372 by checkley75(3666) $\"\"$ $\"About$

You can put this solution on YOUR website!
4x^2-3x+3=0 $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "x=(3+-sqrt[-3^2-4*4*3])/2*4
\n" ); document.write( "x=(3+-sqrt[9-48])/8
\n" ); document.write( "x=(3+-sqrt-39)/8
\n" ); document.write( "x=(3+-6.245i)/8
\n" ); document.write( "x=(3+6.245i)/8
\n" ); document.write( "x=3/8+6.245i/8
\n" ); document.write( "x=3/8+.78i answer.
\n" ); document.write( "x=(3-6.245i)/8
\n" ); document.write( "x=3/8-6.245i/8
\n" ); document.write( "x=3/8-.78i answer. \n" ); document.write( "

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