document.write( "Question 1038912: $\"X%5E2-px%2B4%3E0\"$ then |p| \n" ); document.write( "

Algebra.Com's Answer #653642 by ikleyn(52778) $\"\"$ $\"About$

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document.write( "   = \r\n" );
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document.write( "=  = \r\n" );
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document.write( "=  + .   (1)\r\n" );
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document.write( "In (1), the addend    can be done an arbitrary small by choosing  \"x\",  but  the entire sum (1) remains positive, according to the condition.\r\n" );
document.write( "It means that the second addend   > 0,  or,  in other words,\r\n" );
document.write( " < 4.\r\n" );
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document.write( "Hense,   < 2,   or   < 4.\r\n" );
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document.write( "QED.\r\n" );
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document.write( "Answer.  |p| < 4.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Three plots are shown below with p=3, 4, and 5.\r
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\n" ); document.write( "\n" ); document.write( "Figure. Plots of functions y = $\"x%5E2+-px+%2B+4\"$ , p = 3 (red), 4 (green) and 5 (blue).\r
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