document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1038828>Question 1038828</A>: <I><SPAN STYLE=\"word-break: break-all;\">  If x2 + y2 + 2x + 1 = 0, then the value of x31 + y35 is?\r<BR>\n" );
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document.write( "A) -1<BR>\n" );
document.write( "B) 0<BR>\n" );
document.write( "C) 1<BR>\n" );
document.write( "D) 2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #653610 by </B><A HREF=/tutors/aboutme.mpl?userid=shadhamei@gmail.com><B>shadhamei@gmail.com(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=shadhamei@gmail.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=653610\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Rearrange the equation: \r<BR>\n" );
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document.write( "This is the equation of a circle centered at the point  with radius = 0. That is to say, the solution set of the equation is the single point . \r<BR>\n" );
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document.write( "So  and  \r<BR>\n" );
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document.write( "Any odd power of -1 is -1 and any power of 0 is zero.  </SPAN>\n" );
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