document.write( "Question 1038878: A man has $800 more invested at 4% than at 3%. If the total interest for the two investments is $130. How much is invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #653599 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "x = amount invested at 4%
\n" ); document.write( "y = amount invested at 3%\r
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\n" ); document.write( "\n" ); document.write( "\"A man has $800 more invested at 4% than at 3%\" so we know that \"x=y%2B800\"\r
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\n" ); document.write( "\n" ); document.write( "The amount of interest earned, in one year, for the 4% account is \"x%2A0.04+=+0.04x\"
\n" ); document.write( "The amount of interest earned, in one year, for the 3% account is \"y%2A0.03+=+0.03y\"\r
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\n" ); document.write( "\n" ); document.write( "Put together, the total interest is \"0.04x%2B0.03y\" which is set equal to 130 because this is the total interest for the year.\r
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\n" ); document.write( "\n" ); document.write( "We have \"0.04x%2B0.03y=130\"\r
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\n" ); document.write( "\n" ); document.write( "Use the two equations \"0.04x%2B0.03y=130\" and \"x=y%2B800\" to solve for x and y. Start by using substitution. \r
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\n" ); document.write( "\n" ); document.write( "\"0.04x%2B0.03y=130\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.04%28y%2B800%29%2B0.03y=130\" Plug in \"x=y%2B800\". Solve for y\r
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\n" ); document.write( "\n" ); document.write( "\"0.04y%2B0.04%2A%28800%29%2B0.03y=130\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.04y%2B32%2B0.03y=130\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.07y%2B32=130\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.07y%2B32-32=130-32\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.07y=98\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.07y%2F0.07=98%2F0.07\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=1400\"\r
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\n" ); document.write( "\n" ); document.write( "Now that we know that \"y=1400\", use this to find x.\r
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\n" ); document.write( "\n" ); document.write( "\"x=y%2B800\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=1400%2B800\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=2200\"\r
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\n" ); document.write( "\n" ); document.write( "So we know that \"x=2200\" and \"y=1400\"\r
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\n" ); document.write( "\n" ); document.write( "Final Answer: \r
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\n" ); document.write( "\n" ); document.write( "$2,200 was invested at 4%
\n" ); document.write( "$1,400 was invested at 3%\r
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