document.write( "Question 1038871: Thanks in advance. Please answer my question please :)
\n" ); document.write( "the area of a rectangle is 85cm². Express the perimeter of the rectangle as a function of width (x)
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Algebra.Com's Answer #653592 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let's set up our length and width variables\r
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\n" ); document.write( "\n" ); document.write( "L = length
\n" ); document.write( "W = width\r
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\n" ); document.write( "\n" ); document.write( "The area of any rectangle is \r
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\n" ); document.write( "\n" ); document.write( "area = length*width
\n" ); document.write( "A = L*W\r
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\n" ); document.write( "\n" ); document.write( "Since we're told that the width is x, this means W = x\r
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\n" ); document.write( "\n" ); document.write( "A = L*W
\n" ); document.write( "A = L*x\r
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\n" ); document.write( "\n" ); document.write( "Now divide both sides by x to isolate L\r
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\n" ); document.write( "\n" ); document.write( "A = L*x
\n" ); document.write( "A/x = L*x/x
\n" ); document.write( "L = A/x\r
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\n" ); document.write( "\n" ); document.write( "-------------------------------------\r
\n" ); document.write( "\n" ); document.write( "The width and length are
\n" ); document.write( "W = x
\n" ); document.write( "L = A/x\r
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\n" ); document.write( "\n" ); document.write( "but we know that the area is 85 square cm, so A = 85\r
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\n" ); document.write( "\n" ); document.write( "so,
\n" ); document.write( "W = x
\n" ); document.write( "L = 85/x\r
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\n" ); document.write( "\n" ); document.write( "We use these two expressions to find the perimeter P\r
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\n" ); document.write( "\n" ); document.write( "P = 2*L + 2*W
\n" ); document.write( "P = 2*(85/x) + 2*x
\n" ); document.write( "P = 170/x + 2x
\n" ); document.write( "P = 170/x + (2x^2)/x
\n" ); document.write( "P = (170 + 2x^2)/x\r
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\n" ); document.write( "\n" ); document.write( "So the perimeter is \"P%28x%29=%28170+%2B+2x%5E2%29%2Fx\" where x is the width.
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