document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=89985>Question 89985</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 5 times the first number plus three times the second number eaguals 47, and 10 times the first number minus 4 times the second number equals 54, what are the numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #65357 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=65357\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5X+3Y=47<BR>\n" );
document.write( "10X-4Y=54 NOW MULTIPLY THE FIRST EQUATION BY -2 & ADD:<BR>\n" );
document.write( "-10X-6Y=-94<BR>\n" );
document.write( "--------------------------<BR>\n" );
document.write( "-10Y=-40<BR>\n" );
document.write( "Y=-40/-10<BR>\n" );
document.write( "Y=4 ANSWER<BR>\n" );
document.write( "5X+3*4=47<BR>\n" );
document.write( "5X+12=47<BR>\n" );
document.write( "5X=47-12<BR>\n" );
document.write( "5X=35<BR>\n" );
document.write( "X=35/5<BR>\n" );
document.write( "X=7 ANSWER.<BR>\n" );
document.write( "PTOOF<BR>\n" );
document.write( "10*7-4*4=54<BR>\n" );
document.write( "70-16=54<BR>\n" );
document.write( "54=54 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );