document.write( "Question 89993: Solve the system below using graphing. Write down the solution as an ordered pair.
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document.write( "x+2y= -4
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document.write( "x-y=5\r
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document.write( "Solution( , ) \r
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document.write( "The perimeter of a rectangular field is 460 yards. If the length is 30 yards more than the width, find the dimensions of the field. \n" );
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Algebra.Com's Answer #65355 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! X+2Y=-4 OR 2Y=-X-4 OR Y=-X/2-4/2 OR Y=-X/2-2 (RED LINE) \n" ); document.write( "X-Y=5 \n" ); document.write( "-Y=-X+5 OR Y=X-5 (GREEN LINE) \n" ); document.write( " \n" ); document.write( "ANSWER (2,-3). \n" ); document.write( "------------------------------------------------------------------------ \n" ); document.write( "L=W+30 THEN THE PERIMETERIS: \n" ); document.write( "2(W+30)+2W=460 \n" ); document.write( "2W+60+2W=560 \n" ); document.write( "4W=560-60 \n" ); document.write( "4W=500 \n" ); document.write( "W=500/4 \n" ); document.write( "W=125 YDS. \n" ); document.write( "L=125=30 \n" ); document.write( "L=155 YDS. \n" ); document.write( "PROOF \n" ); document.write( "2*125+2*155=560 \n" ); document.write( "250+310=560 \n" ); document.write( "560=560 \n" ); document.write( " \n" ); document.write( " |