document.write( "Question 90033This question is from textbook algebra
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document.write( ": I need to factor completely, this equation
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document.write( "y^3-12y+36y
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document.write( "a)y(y-9)(y+4)
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document.write( "b.)y(y-6)^2
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document.write( "C.)y(y+6)^2
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document.write( "d.)y(y+12(y-3)\r
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document.write( "these are my options but this is what I have
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document.write( "(y)(y+36)
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document.write( "(y+2)(y-36)
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document.write( "(y+)(y+6)
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document.write( "(-y)(y-6)
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document.write( "I am not sure why I am getting this, can you tell me. \n" );
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Algebra.Com's Answer #65348 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! I BELIEVE YOU LEFT OUT THE ^2 ON THE -12Y. \n" ); document.write( "Y^3-12Y^2+36Y NOW FACTOR OUT THE Y THUS: \n" ); document.write( "Y(Y^2-12Y+36) \n" ); document.write( "Y(Y-6)(Y-6) OR Y(Y-6)^2 OR ANSWER B). \n" ); document.write( " |