document.write( "Question 1038746: The graph of y=ax^2 + bx + c is a parabola with vertical axis of symmetry. The vertex of this parabola is (2,3) and the parabola contains the point (4,4). Find the value of y when x=6.
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Algebra.Com's Answer #653474 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Use the vertex form.\r
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\n" ); document.write( "\n" ); document.write( "where is the vertex of the parabola.\r
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\n" ); document.write( "\n" ); document.write( "Substitute the coordinates for (4,4):\r
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\n" ); document.write( "\n" ); document.write( "and solve for \r
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\n" ); document.write( "\n" ); document.write( "Then you can insert the value of and then expand and rearrange to get the standard form of the function if you wish.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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