document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1038704>Question 1038704</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given that A and B are two independent events with respective probabilities 0.45 and 0.30 compute p(A n B) (b)p(a U B) c)p(A/B)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #653457 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=653457\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> since these are independent events, then p(A and B) is equal to p(A) * p(B).<BR>\n" );
document.write( "p(A) is equal to .45<BR>\n" );
document.write( "p(B) is equal to .30<BR>\n" );
document.write( "p(A and B) is equal to .45 * .30 = .135.\r<BR>\n" );
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document.write( "p(A or B) is equal to p(A) + p(B) - p(A and B).<BR>\n" );
document.write( "this makes p(A or B) equal to .45 + .30 - .135 = .615.\r<BR>\n" );
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document.write( "p(A given B) is equal to p(A and B) / p(B).<BR>\n" );
document.write( "this makes p(A given B) equal to .135/.30 = .45\r<BR>\n" );
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document.write( "note that, since the events are independent, p(A given B) is the same as p(A).\r<BR>\n" );
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