document.write( "Question 1038727: Solve
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Algebra.Com's Answer #653454 by ikleyn(52778)\"\" \"About 
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\n" ); document.write( "sqrt(x+5)+sqrt(x+10)>=2
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\n" ); document.write( "\n" ); document.write( "Figure. Plots y = \"sqrt%28x%2B5%29%2Bsqrt%28x%2B10%29\" and y = 2.\r
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\n" ); document.write( "\n" ); document.write( "Why not? - They are . . . \r
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\n" ); document.write( "\n" ); document.write( "Take x = -5. Then\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28x%2B5%29%2Bsqrt%28x%2B10%29\" = \"sqrt%280%29+%2B+sqrt%285%29\" = \"sqrt%285%29\" is just > 2.\r
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\n" ); document.write( "\n" ); document.write( "Then everything that is greater than -5 satisfies the inequality, too.\r
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\n" ); document.write( "\n" ); document.write( "Answer. The entire domain {x| x >= -5} is the solution.\r
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\n" ); document.write( "\n" ); document.write( "Simply there is an error in the previous solution.\r
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