document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1038719>Question 1038719</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the power-reducing formulas as many times as possible to rewrite the expression in terms of the first power of the cosine.<BR>\n" );
document.write( "2 sin4 2x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #653453 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=653453\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sin^2 2x=(1-cos 4x)/2<BR>\n" );
document.write( "sin^4 2x=(1-2cos 4x+cos^2 4x)/4<BR>\n" );
document.write( "cos^2 4x=(1+cos 8x)/2<BR>\n" );
document.write( "cos^2 4x/4=(1/8)+(cos 8x)/8<BR>\n" );
document.write( "Therefore, sin^4 2x=(1/4)-(cos(4x))/2+[(1/8)+(cos 8x)/8)=(5/8)-[cos(4x)]/2+[cos(8x)/8],<BR>\n" );
document.write( "and 2 sin^4(2x)=(5/4)-cos(4x)+[cos(8x)]/4<BR>\n" );
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