document.write( "Question 1038703: If a tractor travels north at 20 mph and a scooter travels west at 35 mph but leaves an hour later, what is the equation of their distance if f(x) is in terms of time (hours)? \n" ); document.write( "

Algebra.Com's Answer #653412 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
For $\"t%3C=1\"$ , only the first tractor is moving.
\n" ); document.write( " $\"D%5B1%5D\"$ =( $\"0\"$ , $\"20t\"$ )
\n" ); document.write( " $\"D%5B2%5D\"$ =( $\"0\"$ , $\"0\"$ )
\n" ); document.write( " $\"D%5B1-2%5D\"$ =( $\"0\"$ , $\"20t\"$
\n" ); document.write( " $\"abs%28D%5B1-2%5D%29=20t\"$ ( $\"0%3C=t%3C=1\"$ )
\n" ); document.write( "For $\"t%3E1\"$ , both tractors are moving perpendicularly to each other,
\n" ); document.write( "tractor 1 is already 20 miles north of the starting point,
\n" ); document.write( " $\"D%5B1%5D\"$ =( $\"0\"$ , $\"20t\"$ )
\n" ); document.write( " $\"D%5B2%5D\"$ =( $\"-35%28t-1%29\"$ , $\"0\"$ )
\n" ); document.write( " $\"D%5B1-2%5D\"$ =( $\"35%28t-1%29\"$ , $\"20t\"$ )
\n" ); document.write( " $\"abs%28D%5B1-2%5D%29=sqrt%28%2835%28t-1%29%29%5E2%2B%2820t%29%5E2%29\"$
\n" ); document.write( " $\"abs%28D%5B1-2%5D%29=sqrt%281225t%5E2-2450t%2B1225%2B400t%5E2%29\"$
\n" ); document.write( " $\"abs%28D%5B1-2%5D%29=sqrt%281625t%5E2-2450t%2B1225%29\"$ ( $\"t%3E1\"$ )
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\n" ); document.write( "I used $\"t\"$ as the time variable instead of $\"x\"$ .
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