document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=90029>Question 90029</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Simplify\r<BR>\n" );
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document.write( "5th root of -1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #65340 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=65340\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=root%285%2C-1%29 ALIGN=MIDDLE  ALT=\"root%285%2C-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Whenever you take an odd root of a negative number, you don't have to worry about imaginary numbers. So think to yourself: What number multiplied by itself 5 times will get you -1? The number has to be -1 since no other number multiplied by itself will equal -1.\r<BR>\n" );
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document.write( "So\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=root%285%2C-1%29=-1 ALIGN=MIDDLE  ALT=\"root%285%2C-1%29=-1\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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