document.write( "Question 1038686: Find the equation of the circle which passes through (0,0), r=13 and the abscissa of its center is -12 \n" ); document.write( "

Algebra.Com's Answer #653396 by Fombitz(32388) $\"\"$ $\"About$

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So the general equation of a circle is,
\n" ); document.write( " $\"%28x-h%29%5E2%2B%28y-k%29%5E2=R%5E2\"$
\n" ); document.write( "So we know,
\n" ); document.write( " $\"R=13\"$
\n" ); document.write( " $\"k=-12\"$
\n" ); document.write( "Substituting,
\n" ); document.write( " $\"%28x-h%29%5E2%2B%28y%2B12%29%5E2=169\"$
\n" ); document.write( "Using the point,
\n" ); document.write( " $\"%280-h%29%5E2%2B%280%2B12%29%5E2=169\"$
\n" ); document.write( " $\"h%5E2%2B144=169\"$
\n" ); document.write( " $\"h%5E2=25\"$
\n" ); document.write( " $\"h=0+%2B-+5\"$
\n" ); document.write( "There are two solutions,
\n" ); document.write( " $\"%28x-5%29%5E2%2B%28y-12%29%5E2=169\"$
\n" ); document.write( "and
\n" ); document.write( " $\"%28x%2B5%29%5E2%2B%28y-12%29%5E2=169\"$
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