document.write( "Question 1038677: Find the vertex and than graph\r
\n" ); document.write( "\n" ); document.write( "2x^2+8x+16=0
\n" ); document.write( "By using:\r
\n" ); document.write( "\n" ); document.write( "X= -b/2a\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #653390 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
You should study what is presented here, very closely:
\n" ); document.write( "Change a quadratic equation from general form to standard form - video\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "You can directly read the vertex coordinates from the standard form equation. That gives information for graphing.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Observe that your given equation is equivalent to \"x%5E2%2B4x%2B8=0\", so you should use this as your starting general-form equation.
\n" ); document.write( "--
\n" ); document.write( "\"xCoordinateofVertex=-b%2F%282a%29=-4%2F%282%2A1%29=-2\"------Actually this is for the function \"y=x%5E2%2B4x%2B8\". The vertex occurs at \"x=-2\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The only realistic graph for \"x%5E2%2B4x%2B8=0\" would be TWO points on a single numberline, only if these are real numbers and not containing imaginary parts. The zeros for your equation are .\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "These are NOT real numbers.
\n" ); document.write( "
\n" );