document.write( "Question 1038621: Ashley, Brian, Caroline, David and Elaine are all different ages.
\n" ); document.write( "The sum of their ages is 110.
\n" ); document.write( "Ashley is the oldest and David is the youngest at 19.
\n" ); document.write( "Brian has the median age and he is younger than Caroline, who has the mean age.
\n" ); document.write( "Work out the age of each person.\r
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Algebra.Com's Answer #653369 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "If B is the median, then two of the others must be older and two must be younger. A is one of the older because she is the oldest of the 5, and C is older because that fact is given. That means that E is second to the youngest because D is youngest.\r
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\n" ); document.write( "\n" ); document.write( "So we have them in order of age from youngest to oldest:\r
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\n" ); document.write( "\n" ); document.write( "D E B C A\r
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\n" ); document.write( "\n" ); document.write( "Since the sum of their ages is 110 and C is the mean age, C is 110 divided by 5, or 22.\r
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\n" ); document.write( "\n" ); document.write( "Since D is 19 and they are all different ages, E and B must be 20 and 21 respectively.\r
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\n" ); document.write( "\n" ); document.write( "The sum of the ages of D, E, B, and C is 82. 110 minus 82 is 28. Therefore:\r
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\n" ); document.write( "\n" ); document.write( "D is 19
\n" ); document.write( "E is 20
\n" ); document.write( "B is 21
\n" ); document.write( "C is 22
\n" ); document.write( "A is 28\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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