document.write( "Question 1038621: Ashley, Brian, Caroline, David and Elaine are all different ages.
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document.write( "The sum of their ages is 110.
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document.write( "Ashley is the oldest and David is the youngest at 19.
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document.write( "Brian has the median age and he is younger than Caroline, who has the mean age.
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document.write( "Work out the age of each person.\r
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Algebra.Com's Answer #653369 by solver91311(24713) You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If B is the median, then two of the others must be older and two must be younger. A is one of the older because she is the oldest of the 5, and C is older because that fact is given. That means that E is second to the youngest because D is youngest.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So we have them in order of age from youngest to oldest:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "D E B C A\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the sum of their ages is 110 and C is the mean age, C is 110 divided by 5, or 22.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since D is 19 and they are all different ages, E and B must be 20 and 21 respectively.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The sum of the ages of D, E, B, and C is 82. 110 minus 82 is 28. Therefore:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "D is 19 \n" ); document.write( "E is 20 \n" ); document.write( "B is 21 \n" ); document.write( "C is 22 \n" ); document.write( "A is 28\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( " |