document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1038646>Question 1038646</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The radius of a big outer cirle that is shaded is 6 inches long and the diameter of a small inner circle is 8 inches long.  Find the area of the shaded region of the larger outer circle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #653361 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=653361\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "Assuming the 8-inch diameter circle is wholly contained in the 6-inch radius circle and that the shaded area is that part of the larger circle that is not contained in the smaller circle, then the shaded area is the area of the large circle minus the area of the small circle.\r<BR>\n" );
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document.write( "Since the diameter of the small circle is 8 inches, the radius is 4 inches.  Hence:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ A_{shaded}\ =\ A_l\ -\ A_s\ =\ \pi{6^2}\ -\ \pi{4^2}\ =\ 36\pi\ -\ 16\pi\ =\ 20\pi\ \text{in^2}\">\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi}\ +\ 1\ =\ 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \ \\r\"> </SPAN>\n" );
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