document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1038636>Question 1038636</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A solution containing 30% juice is mixed with a solution containing 10% juice to make a 100 gallons of a 12% juice mixture.  How much of the juice somution was used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #653343 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=653343\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the 30% juice. Then:<BR>\n" );
document.write( ".3n+.1(100-n)=.12(100)<BR>\n" );
document.write( ".3n+10-.1n=.12(100)<BR>\n" );
document.write( ".2n=2<BR>\n" );
document.write( "n=10 gallons of 30% juice, and 90 gallons of 10% juice needed!!!!!!!!!!!! </SPAN>\n" );
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