document.write( "Question 1038579: Hi
\n" ); document.write( "Betty has 1/3 as many pins as susan.when susan gave away 55 pins, the number of pins Betty has is twice the number susan has left..how many pins does susan have at first.\r
\n" ); document.write( "\n" ); document.write( "thanks
\n" ); document.write( "

Algebra.Com's Answer #653333 by jorel555(1290)\"\" \"About 
You can put this solution on YOUR website!
Let s be susan, b be betty. Then:
\n" ); document.write( "s=3b
\n" ); document.write( "s-55=b/2. So:
\n" ); document.write( "3b-55=b/2
\n" ); document.write( "6b-110=b
\n" ); document.write( "5b=110
\n" ); document.write( "b=22
\n" ); document.write( "s=66
\n" ); document.write( "Betty has 22 pins to start, Susan has 66!!!!!!!!!!!!!!
\n" ); document.write( "
\n" );