document.write( "Question 1038604: If 2sin^2theta -cos^2theta=2 then theta=? \n" ); document.write( "
Algebra.Com's Answer #653314 by ikleyn(52795)\"\" \"About 
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\n" ); document.write( "If 2sin^2theta -cos^2theta=2 then theta=?
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document.write( "\"2sin%5E2%28theta%29+-cos%5E2%28theta%29\" = \"2sin%5E2%28theta%29+-+%281-sin%5E2%28theta%29%29\" = \"3sin%5E2%28theta%29+-1\".\r\n" );
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document.write( "Therefore, if \"2sin%5E2%28theta%29+-cos%5E2%28theta%29\" = 2 then\r\n" );
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document.write( "\"3sin%5E2%28theta%29+-1\" = \"2\"  --->\r\n" );
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document.write( "\"3sin%5E2%28theta%29\" = \"3\"  --->\r\n" );
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document.write( "\"sin%5E2%28theta%29\" = \"1\"  --->\r\n" );
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document.write( "\"sin%28theta%29\" = +/-\"1\"  --->\r\n" );
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document.write( "\"theta\" = \"pi%2F2+%2B+2k%2Api\"  or  \"theta\" = \"-pi%2F2+%2B+2k%2Api\", k = 0, +/-1, +/-2, . . . \r\n" );
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document.write( "Answer.  \"theta\" = \"pi%2F2+%2B+k%2Api\",  k = 0, +/-1, +/-2, . . . \r\n" );
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