document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1038493>Question 1038493</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man can row three-quarters of a kilometer against the stream in 45/4 minutes. The speed (in km/hr) of the man in still water ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #653219 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=653219\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A man can row three-quarters of a kilometer against the stream in 45/4 minutes. The speed (in km/hr) of the man in still water ?<BR>\n" );
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document.write( "r = rowing speed (in still water)<BR>\n" );
document.write( "c = current<BR>\n" );
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document.write( "r - c = d/t = (3/4)km/(45/4)/60))hr<BR>\n" );
document.write( "r - c = (3/4)/(45/240) km/hr<BR>\n" );
document.write( "r - c = 720/135 km/hr<BR>\n" );
document.write( "r - c = 16/3 km/hr<BR>\n" );
document.write( "r = c + 16/3 km/hr<BR>\n" );
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document.write( "He can row 16/3 km/hr plus whatever c for the current is.<BR>\n" );
document.write( "The current wasn't spec'ed. </SPAN>\n" );
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