document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1038462>Question 1038462</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find tan &#952; + sin &#952; for the angle &#952; shown\r<BR>\n" );
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document.write( "Right triangle:<BR>\n" );
document.write( "Opp:2<BR>\n" );
document.write( "Adj:3<BR>\n" );
document.write( "Hyp:? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #653169 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=653169\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It is a 2,3,sqrt(13) triangle<BR>\n" );
document.write( "tangent is opp/adj=(2/3)<BR>\n" );
document.write( "sine is opp/hyp=2/sqrt (13)<BR>\n" );
document.write( "Add them: common denominator is 3sqrt(13); numerator is 2 sqrt (13)+6,\r<BR>\n" );
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document.write( "[2 sqrt(13)+6]/3*sqrt(13)<BR>\n" );
document.write( "after rationalizing the denominator<BR>\n" );
document.write( "sqrt(13)(2sqrt(13)+6sqrt(13)]/39; the 39 comes from 3*sqrt(13)(sqrt (13)<BR>\n" );
document.write( "[26+6 sqrt(13)]/39.  It may be written other ways. </SPAN>\n" );
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