document.write( "Question 1038464: A machine has fifteen identical components that function independently. It will stop working if three or more of the components fail. If the probability that an individual component fails is 0.08, find the probability that the machine will be working
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Algebra.Com's Answer #653168 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You want the probability that the machine will be working, so you want the probability of 2 or fewer occurrences of a failure in 15 trials given the probability of success on any given trial is 0.08.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The probability of \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Where \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since you are looking for the probability of 2 or fewer, you need the probability of 0 plus the probability of 1 plus the probability of 2, that is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "An easier way to get the answer, given that you have MS Excel on your PC or Numbers on your MAC, is to open a spreadsheet and type the following: \n" ); document.write( " \r\n" ); document.write( " =BINOMDIST(2,15,0.08,TRUE)\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( " |