document.write( "Question 1038417: X+2y-2=3
\n" ); document.write( "3x-y+2z=2
\n" ); document.write( "2x-2y+3z=2
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Algebra.Com's Answer #653153 by Alan3354(69443)\"\" \"About 
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X+2y-2=3 --> x+2y = 5 --> x = -2y+5
\n" ); document.write( "3x-y+2z=2
\n" ); document.write( "2x-2y+3z=2
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\n" ); document.write( "Sub for x in the 2nd & 3rd eqns
\n" ); document.write( "3(-2y+5) - y + 2z = 2 --> -7y + 2z = -13
\n" ); document.write( "2(-2y+5) -2y + 3z = 2 --> -6y + 3z = -8
\n" ); document.write( "-------
\n" ); document.write( "-7y + 2z = -13 times 3 --> -21y + 6z = -39
\n" ); document.write( "-6y + 3z = -8 times 2 --> -16y + 6z = -16
\n" ); document.write( "----------
\n" ); document.write( "-21y + 6z = -39
\n" ); document.write( "-16y + 6z = -16
\n" ); document.write( "----------------------- Subtract
\n" ); document.write( "5y = -23
\n" ); document.write( "y = -23/5
\n" ); document.write( "------
\n" ); document.write( "-6y + 3z = -8
\n" ); document.write( "138/5 + 3z = -8
\n" ); document.write( "3z = -178/5
\n" ); document.write( "z = -178/15
\n" ); document.write( "--------
\n" ); document.write( "x = -2y + 5
\n" ); document.write( "z = -21/5\r
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