document.write( "Question 1038397: A truck can be rented from company A for $80 a day plus $0.60 per mile. Company B charges 30$ a day plus $0.80 per mile to rent the same truck. How many miles must be driven in a day to make the rental cost for Company A a better deal than Comoany B's?
\n" );
document.write( "For company A to have a better deal, the truck must be driven more than __ miles per day. \n" );
document.write( "
Algebra.Com's Answer #653109 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A truck can be rented from company A for $80 a day plus $0.60 per mile. Company B charges 30$ a day plus $0.80 per mile to rent the same truck. How many miles must be driven in a day to make the rental cost for Company A a better deal than Company B's? \n" ); document.write( "------------------- \n" ); document.write( "A(m) = 80 + 0.60m \n" ); document.write( "B(m) = 30 + 0.8m \n" ); document.write( "--------------------------- \n" ); document.write( "For company A to have a better deal, the truck must be driven more than __ miles per day. \n" ); document.write( "Solve:: \n" ); document.write( "80 + 0.6m < 30 + 0.8m \n" ); document.write( "------- \n" ); document.write( "50 < 0.2m \n" ); document.write( "m > 5000/2 = 2500 miles \n" ); document.write( "--------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------------- \n" ); document.write( " |