document.write( "Question 1038397: A truck can be rented from company A for $80 a day plus $0.60 per mile. Company B charges 30$ a day plus $0.80 per mile to rent the same truck. How many miles must be driven in a day to make the rental cost for Company A a better deal than Comoany B's?
\n" ); document.write( "For company A to have a better deal, the truck must be driven more than __ miles per day.
\n" ); document.write( "

Algebra.Com's Answer #653109 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A truck can be rented from company A for $80 a day plus $0.60 per mile. Company B charges 30$ a day plus $0.80 per mile to rent the same truck. How many miles must be driven in a day to make the rental cost for Company A a better deal than Company B's?
\n" ); document.write( "-------------------
\n" ); document.write( "A(m) = 80 + 0.60m
\n" ); document.write( "B(m) = 30 + 0.8m
\n" ); document.write( "---------------------------
\n" ); document.write( "For company A to have a better deal, the truck must be driven more than __ miles per day.
\n" ); document.write( "Solve::
\n" ); document.write( "80 + 0.6m < 30 + 0.8m
\n" ); document.write( "-------
\n" ); document.write( "50 < 0.2m
\n" ); document.write( "m > 5000/2 = 2500 miles
\n" ); document.write( "---------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "----------------
\n" ); document.write( "
\n" );